30x^2-19x-4=0

Solution for 30x^2-19x-4=0 equation:

30x^2-19x-4=0

a = 30; b = -19; c = -4;
Δ = b2-4ac
Δ = -192-4·30·(-4)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-29}{2*30}=\frac{-10}{60}
=-1/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+29}{2*30}=\frac{48}{60}
=4/5
$